sequential_regression

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sequential_regression [2024/06/12 08:21] – [r] hkimscilsequential_regression [2024/06/12 08:30] (current) – [r] hkimscil
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 <code> <code>
-pcor.test(datavar$bankaccount, datavar$income, datavar$famnum) +pp.b.i <- pcor.test(datavar$bankaccount, datavar$income, datavar$famnum) 
-pcor.test(datavar$bankaccount, datavar$famnum, datavar$income)+p.b.i 
 +p.b.i$estimate
  
-spcor.test(datavar$bankaccount, datavar$income, datavar$famnum) +p.b.f <- pcor.test(datavar$bankaccount, datavar$famnum, datavar$income) 
-spcor.test(datavar$bankaccount, datavar$famnum, datavar$income)+p.b.f 
 +p.b.f$estimate 
 + 
 +sp.b.i <- spcor.test(datavar$bankaccount, datavar$income, datavar$famnum) 
 +sp.b.i 
 +sp.b.i$estimate 
 +sp.b.f <- spcor.test(datavar$bankaccount, datavar$famnum, datavar$income) 
 +sp.b.f 
 +sp.b.f$estimate 
 + 
 + 
 +zc.b.i <- cor(datavar$bankaccount, datavar$income) 
 +zc.b.i  
 +zc.b.f <- cor(datavar$bankaccount, datavar$famnum) 
 +zc.b.f 
 + 
 +zc.b.i^2 - (sp.b.i$estimate)^2 
 +zc.b.f^2 - (sp.b.f$estimate)^2
  
-cor(datavar$bankaccount, datavar$income) 
-cor(datavar$bankaccount, datavar$famnum) 
 </code> </code>
 . . .  . . . 
 <code> <code>
-> pcor.test(datavar$bankaccount, datavar$income, datavar$famnum) +pp.b.i <- pcor.test(datavar$bankaccount, datavar$income, datavar$famnum) 
-   estimate    p.value statistic  n gp  Method +> p.b.i 
-1 0.7825112 0.01267595  3.325102 10  1 pearson +  estimate p.value statistic  n gp  Method 
-> pcor.test(datavar$bankaccount, datavar$famnum, datavar$income) +  0.7825 0.01268     3.325 10  1 pearson 
-   estimate    p.value statistic  n gp  Method +p.b.i$estimate 
-1 -0.672856 0.04702022 -2.406425 10  1 pearson +[1] 0.7825 
-+>  
-> spcor.test(datavar$bankaccount, datavar$income, datavar$famnum) +> p.b.f <- pcor.test(datavar$bankaccount, datavar$famnum, datavar$income) 
-   estimate  p.value statistic  n gp  Method +> p.b.f 
-1 0.5646726 0.113182  1.810198 10  1 pearson +  estimate p.value statistic  n gp  Method 
-> spcor.test(datavar$bankaccount, datavar$famnum, datavar$income) + -0.6729 0.04702    -2.406 10  1 pearson 
-    estimate   p.value statistic  n gp  Method +p.b.f$estimate 
-1 -0.4086619 0.2748117 -1.184655 10  1 pearson+[1] -0.6729 
 + 
 +> sp.b.i <- spcor.test(datavar$bankaccount, datavar$income, datavar$famnum) 
 +> sp.b.i 
 +  estimate p.value statistic  n gp  Method 
 +  0.5647  0.1132      1.81 10  1 pearson 
 +sp.b.i$estimate 
 +[1] 0.5647 
 +> sp.b.f <- spcor.test(datavar$bankaccount, datavar$famnum, datavar$income) 
 +> sp.b.f 
 +  estimate p.value statistic  n gp  Method 
 + -0.4087  0.2748    -1.185 10  1 pearson 
 +> sp.b.f$estimate 
 +[1] -0.4087 
 +>  
 +>  
 +> zc.b.i <- cor(datavar$bankaccount, datavar$income) 
 +> zc.b.i  
 +[1] 0.7944 
 +> zc.b.f <- cor(datavar$bankaccount, datavar$famnum) 
 +> zc.b.f 
 +[1] -0.6923 
 +>  
 +> zc.b.i^2 - (sp.b.i$estimate)^2 
 +[1] 0.3123 
 +> zc.b.f^2 - (sp.b.f$estimate)^2 
 +[1] 0.3123 
 +
  
  
-  
 </code> </code>
  
sequential_regression.1718148065.txt.gz · Last modified: 2024/06/12 08:21 by hkimscil

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