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deriviation_of_a_and_b_in_a_simple_regression [2025/08/01 17:03] hkimscilderiviation_of_a_and_b_in_a_simple_regression [2025/08/05 06:24] (current) hkimscil
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 \begin{eqnarray*} \begin{eqnarray*}
-\sum{(Y_i - \hat{Y_i})^2} & = & \sum{(Y_i - (a + bX_i))^2}  \;\;\; \because \hat{Y_i} = a + bX_i \\+\sum{(Y_i - \hat{Y_i})^2}  
 +& = & \sum{(Y_i - (a + bX_i))^2}  \;\;\; \because \hat{Y_i} = a + bX_i \\
 & = & \text{SSE or SS.residual} \;\;\; \text{(and this should be the least value.)} & = & \text{SSE or SS.residual} \;\;\; \text{(and this should be the least value.)}
 \end{eqnarray*} \end{eqnarray*}
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 \text{for a (constant)} \\  \text{for a (constant)} \\ 
 \\ \\
-\dfrac{\text{d}}{\text{dv}} \sum{(Y_i - (a + bX_i))^2} & = & \sum \dfrac{\text{d}}{\text{dv}} {(Y_i - (a + bX_i))^2} \\  +\dfrac{\text{d}}{\text{da}} \sum{(Y_i - (a + bX_i))^2}  
-& \sum{(Y_i - (a + bX_i))} * (-1) \;\;\;\\\ +& = & \sum \dfrac{\text{d}}{\text{da}} {(Y_i - (a + bX_i))^2} \\ 
-& \because & \dfrac{\text{d}}{\text{dv for a}} (Y_i - (a+bX_i)) = -1 \\+& & \because {(Y_i - (a + bX_i))^2\text{residual}^2 \\ 
 +& & \therefore{} \\ 
 +& = & \sum \dfrac{\text{dresidual}^2} {da}  \\ 
 += & \sum \dfrac{\text{dresidual}^2}{\text{dresidual}} * \dfrac{\text{dresidual}}{\text{da}} \\ 
 +& = & \sum{2 * \text{residual}} * {\dfrac{\text{dresidual}}{\text{da}}} \;\;\;\; \\ 
 +& = & \sum{2 * \text{residual}} * {\dfrac{d{(Y_i - (a + bX_i))}}{\text{da}}} \;\;\;\; \\ 
 +& \sum{2 * \text{residual}} * (0 - 1 - 0) \;\;\;\; \\ 
 +& & \because{Y_i = 0; \;\;\; a = 1; \;\;\; bX_i = 0} \\ 
 +& = & \sum{2 * \text{residual}} * (-1) \;\;\;\; \\
 & = & -2 \sum{(Y_i - (a + bX_i))} \\  & = & -2 \sum{(Y_i - (a + bX_i))} \\ 
 \\ \\
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 \text{for b, (coefficient)} \\  \text{for b, (coefficient)} \\ 
 \\ \\
-\dfrac{\text{d}}{\text{dv}} \sum{(Y_i - (a + bX_i))^2}  & = & \sum \dfrac{\text{d}}{\text{dv}} {(Y_i - (a + bX_i))^2} \\ +\dfrac{\text{d}}{\text{db}} \sum{(Y_i - (a + bX_i))^2}  & = & \sum \dfrac{\text{d}}{\text{db}} {(Y_i - (a + bX_i))^2} \\ 
 & = & \sum{2 (Y_i - (a + bX_i))} * (-X_i) \;\;\;\; \\ & = & \sum{2 (Y_i - (a + bX_i))} * (-X_i) \;\;\;\; \\
 & \because & \dfrac{\text{d}}{\text{dv for b}} (Y_i - (a+bX_i)) = -X_i \\ & \because & \dfrac{\text{d}}{\text{dv for b}} (Y_i - (a+bX_i)) = -X_i \\
deriviation_of_a_and_b_in_a_simple_regression.1754035387.txt.gz · Last modified: 2025/08/01 17:03 by hkimscil

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