c:ma:2021:sample_questions
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c:ma:2021:sample_questions [2021/10/07 01:11] – created hkimscil | c:ma:2021:sample_questions [2021/10/07 01:26] (current) – hkimscil | ||
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8. 검증결과의 결론을 내리시오. | 8. 검증결과의 결론을 내리시오. | ||
- | \begin{eqnarray} | + | \begin{eqnarray*} |
- | s_p^2 & = & \displaystyle \frac{SS_a+SS_b}{df_a+df_b} | + | s_p^2 & = & \displaystyle \frac{SS_a+SS_b}{df_a+df_b} |
- | & = & \frac{1020 + 1300} {29 + 29} | + | & = & \frac{1020 + 1300} {29 + 29} \\ |
- | & = & \frac{2320} {58} | + | & = & \frac{2320} {58} \\ |
- | \end{eqnarray} | + | & = & 40 |
+ | \end{eqnarray*} | ||
+ | \begin{eqnarray*} | ||
+ | se & = & \displaystyle s_{\overline{X_a}-\overline{X_b}} \\ | ||
+ | & = & \sqrt{\frac{S_p^2}{n_a} + \frac{S_p^2}{n_b}} \\ | ||
+ | & = & \sqrt{ \frac{40}{30} + \frac{40}{30} } \\ | ||
+ | & = & 1.632993 | ||
+ | \end{eqnarray*} | ||
+ | |||
+ | \begin{eqnarray*} | ||
+ | t_\text{calculated} & = & \displaystyle \frac{\text{difference}} {\text{random error}} \\ | ||
+ | & = & \displaystyle \frac{\text{difference}} {\text{standard error}} \\ | ||
+ | & = & \displaystyle \frac{30-20} {1.632993} \\ | ||
+ | & = & 6.123724 | ||
+ | \end{eqnarray*} | ||
+ | |||
+ | < | ||
+ | > 2320/58 | ||
+ | [1] 40 | ||
+ | > sqrt(8/3) | ||
+ | [1] 1.632993 | ||
+ | > 10/ | ||
+ | [1] 6.123724 | ||
+ | > qt(0.975, 58) | ||
+ | [1] 2.001717 | ||
+ | > | ||
+ | </ | ||
+ | \begin{eqnarray*} | ||
+ | t_\text{critical}(\alpha=0.05, | ||
+ | \end{eqnarray*} | ||
c/ma/2021/sample_questions.1633536694.txt.gz · Last modified: 2021/10/07 01:11 by hkimscil