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bayes_theorem [2025/09/21 18:55] hkimscilbayes_theorem [2025/09/21 22:35] (current) hkimscil
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 \text{heance }   \nonumber \\ \text{heance }   \nonumber \\
 P(A \cap B) & = & P(A \mid B) * P(B) \;\; \text{ and    \nonumber \\ P(A \cap B) & = & P(A \mid B) * P(B) \;\; \text{ and    \nonumber \\
-P(B \cap A) & = & P(B \mid A) * P(A) \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad (1) \\+P(B \cap A) & = & P(B \mid A) * P(A) \qquad\qquad\qquad\qquad\qquad\qquad\qquad (1) \\
  \nonumber \\  \nonumber \\
  \nonumber \\  \nonumber \\
 P(B) & = & P(A \cap B) + P(\neg A \cap B)  \nonumber \\ P(B) & = & P(A \cap B) + P(\neg A \cap B)  \nonumber \\
 & = & P(B \cap A) + P(B \cap \neg A)  \nonumber \\ & = & P(B \cap A) + P(B \cap \neg A)  \nonumber \\
-& = & P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A) \qquad\qquad\qquad\qquad\qquad (2) \\+& = & P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A) \qquad\qquad (2) \\
 \\ \\
 \\ \\
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 & = & \dfrac{P(B \cap A)}{P(B)} \;\;\; \text{ from (1) and (2)  } \nonumber  \\ & = & \dfrac{P(B \cap A)}{P(B)} \;\;\; \text{ from (1) and (2)  } \nonumber  \\
 & = & \dfrac {(1)} {(2)} \nonumber \\ & = & \dfrac {(1)} {(2)} \nonumber \\
-& = & \dfrac {P(B \mid A) * P(A)} {P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A)} \qquad\qquad\qquad\qquad\qquad (3) \\+& = & \dfrac {P(B \mid A) * P(A)} {P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A)}  \qquad\qquad (3) \\
  
  
bayes_theorem.1758448501.txt.gz · Last modified: by hkimscil

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