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bayes_theorem [2025/09/20 20:40] hkimscilbayes_theorem [2025/09/21 22:35] (current) hkimscil
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 ====== Bayes' Theorem ====== ====== Bayes' Theorem ======
-\begin{eqnarray} +<WRAP left> 
-\text{c.f.,} \nonumber \\ +\begin{eqnarray*
-& & P(A|B) = \dfrac{P(A \cap B)}{P(B)}  \nonumber \\ +P(A \mid B) \dfrac{P(A \cap B)}{P(B)}  \nonumber \\ 
-& & P(B|A) = \dfrac{P(B \cap A)}{P(A)}  \nonumber \\ +P(B \mid A) \dfrac{P(B \cap A)}{P(A)}  \nonumber \\ 
-& &\text{heance }   \nonumber \\ +\text{heance }   \nonumber \\ 
-& & P(A \cap B) = P(A \mid B) * P(B) \text{and    \nonumber \\ +P(A \cap B) P(A \mid B) * P(B) \;\; \text{ and    \nonumber \\ 
-& & P(B \cap A) = P(B \mid A) * P(A)  \\+P(B \cap A) P(B \mid A) * P(A) \qquad\qquad\qquad\qquad\qquad\qquad\qquad (1) \\
  \nonumber \\  \nonumber \\
  \nonumber \\  \nonumber \\
 P(B) & = & P(A \cap B) + P(\neg A \cap B)  \nonumber \\ P(B) & = & P(A \cap B) + P(\neg A \cap B)  \nonumber \\
 & = & P(B \cap A) + P(B \cap \neg A)  \nonumber \\ & = & P(B \cap A) + P(B \cap \neg A)  \nonumber \\
-& = & P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A) \\ +& = & P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A) \qquad\qquad (2) \\ 
- \nonumber \\ +\\ 
-\text{by the way  } \nonumber   \\ +\\ 
-P(A|B) & = & \dfrac{P(A \cap B)}{P(B)} \nonumber  \\+P(A \mid B) & = & \dfrac{P(A \cap B)}{P(B)} \nonumber  \\ 
 +& = & \dfrac{P(B \cap A)}{P(B)} \;\;\; \text{ from (1) and (2)  } \nonumber  \\
 & = & \dfrac {(1)} {(2)} \nonumber \\ & = & \dfrac {(1)} {(2)} \nonumber \\
-& = & \dfrac {P(B \mid A) * P(A)} {P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A)} \\+& = & \dfrac {P(B \mid A) * P(A)} {P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A)}  \qquad\qquad (3) \\ 
 + 
 + 
 +\end{eqnarray*} 
 +</WRAP> 
 +<WRAP clear /> 
 + 
 + 
 + 
 +<WRAP box left> 
 +\begin{eqnarray} 
 +& & P(A \mid B) = \dfrac{P(A \cap B)}{P(B)}  \nonumber \\ 
 +& & P(B \mid A) = \dfrac{P(B \cap A)}{P(A)}  \nonumber \\ 
 +& & \text{heance }   \nonumber \\ 
 +& & P(A \cap B) = P(A \mid B) * P(B) \;\; \text{ and    \nonumber \\ 
 +& & P(B \cap A) = P(B \mid A) * P(A)  \\ 
 + \nonumber \\ 
 + \nonumber \\ 
 +& & P(B) = P(A \cap B) + P(\neg A \cap B)  \nonumber \\ 
 +& & = P(B \cap A) + P(B \cap \neg A)  \nonumber \\ 
 +& & = P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A) \\ 
 + \nonumber \\ 
 + \nonumber \\ 
 +& & \text{suppose that we not know  }  P(B) \nonumber \\ 
 +& & P(A \mid B) = \dfrac{P(A \cap B)}{P(B)} \nonumber  \\ 
 +& & = \dfrac{P(B \cap A)}{P(B)} \;\;\; \text{ from (1) and (2)  } \nonumber  \\ 
 +& & = \dfrac {(1)} {(2)} \nonumber \\ 
 +& & = \dfrac {P(B \mid A) * P(A)} {P(B \mid A) * P(A) + P(B \mid \neg A) * P(\neg A)} \\
 \end{eqnarray} \end{eqnarray}
 +</WRAP>
 +<WRAP clear />
  
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bayes_theorem.1758368402.txt.gz · Last modified: by hkimscil

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