b:head_first_statistics:using_the_normal_distribution
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| b:head_first_statistics:using_the_normal_distribution [2025/10/08 12:10] – [Apply a continuity correction] hkimscil | b:head_first_statistics:using_the_normal_distribution [2025/10/09 06:26] (current) – [X - Y] hkimscil | ||
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| rnorm(n, mean = 0, sd = 1) | rnorm(n, mean = 0, sd = 1) | ||
| </ | </ | ||
| - | </ | ||
| - | {{ : | ||
| - | |||
| - | |||
| + | {{: | ||
| 따라서 | 따라서 | ||
| $$P(X + Y < 380) = 0.9082409 $$ | $$P(X + Y < 380) = 0.9082409 $$ | ||
| + | </ | ||
| ===== exercise ===== | ===== exercise ===== | ||
| - | < | + | < |
| Julie’s matchmaker is at it again. What's the **probability that a man will be at least 5 inches taller than a woman**? In Statsville, the height of men in inches is distributed as N(71, 20.25), and the height of women in inches is distributed as N(64, 16). | Julie’s matchmaker is at it again. What's the **probability that a man will be at least 5 inches taller than a woman**? In Statsville, the height of men in inches is distributed as N(71, 20.25), and the height of women in inches is distributed as N(64, 16). | ||
| </ | </ | ||
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| **probability that a man will be at least 5 inches taller than a woman**? = " | **probability that a man will be at least 5 inches taller than a woman**? = " | ||
| + | |||
| \begin{align*} | \begin{align*} | ||
| P(X > F + 5) & = P(X - F > 5) | P(X > F + 5) & = P(X - F > 5) | ||
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| ===== Pool Puzzle ===== | ===== Pool Puzzle ===== | ||
| <wrap # | <wrap # | ||
| - | < | + | < |
| X < 3 ---- <wrap spoiler> X < 2.5 </ | X < 3 ---- <wrap spoiler> X < 2.5 </ | ||
| X > 3 ---- <wrap spoiler> X > 3.5 </ | X > 3 ---- <wrap spoiler> X > 3.5 </ | ||
b/head_first_statistics/using_the_normal_distribution.1759893052.txt.gz · Last modified: by hkimscil