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        <title>note</title>
        <link>http://www.commres.net/c/ps1-1/2023/schedule/note?rev=1694993941&amp;do=diff</link>
        <description># pnorm(1.5): mean = 0, sd = 1 인 
# 분포에서 1.5 score에서의 percentage (왼쪽부분)
pnorm(1.5, mean=0, sd=1)
# 수업에서 아래는 각각 68, 95, 99 % 설명 
# 그러나 사실은 조금 다름
pnorm(1)-pnorm(-1)
pnorm(2)-pnorm(-2)
pnorm(3)-pnorm(-3)

# .95 부분을 찾기 위해서는
# qnorm을 사용해 본다
# qnorm(percent, mean=0, sd=1)
perc68h &lt;- .68 + (.32*.5)
perc68l &lt;- .32*.5
qnorm(perc68h, mean=0, sd=1)
qnorm(perc68l)

ahi2 &lt;- qnorm(.975)
alo2 &lt;- qnorm(.025)

ahi2
alo2
pnorm(ahi2)-pnorm(alo2)

(1-1/200)
ahi3 &lt;- qnorm(.995)
alo3 &lt;- qnorm(.005)
pnorm(ahi3)-pnorm(…</description>
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