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        <title>COMMunication&lt;br /&gt;RESearch.NET - c:ms:2026:schedule</title>
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       <dc:date>2026-06-02T07:40:53+00:00</dc:date>
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        <title>COMMunication<br />RESearch.NET</title>
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        <dc:format>text/html</dc:format>
        <dc:date>2026-03-25T01:20:21+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>lecture_note_week_03</title>
        <link>http://www.commres.net/c/ms/2026/schedule/lecture_note_week_03?rev=1774401621&amp;do=diff</link>
        <description>*  variance = SS / df 
	*  SS = Sum of Sqaure (of (something))
	*  something = error, residual, deviation score (ds), (X변인의) total
	*  df = n - 1 
	*  Why n-1
		*  $s^2 = \widehat{\sigma}$ 을 위해서 분산값을 사용하는데 $\text{SS}$ 값을 구할 때 샘플의 평균을 이용하면 그 값이 항상 최소값이 되어서 이를 만회하기 위해서 n-1을 쓴다</description>
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        <dc:date>2026-05-21T01:06:17+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>w10.lecture.note</title>
        <link>http://www.commres.net/c/ms/2026/schedule/w10.lecture.note?rev=1779325577&amp;do=diff</link>
        <description>Correlation and Regression

	*  correlation
	*  regression
	*  deriviation of a and b in a simple regression regression 에서 a 와 b 구하기
		*  chain rules
		*  gradient descent



rm(list=ls())

rnorm2 &lt;- function(n,mean,sd) { 
  mean + sd * scale(rnorm(n)) 
}
ss &lt;- function(x) {
  sum((x-mean(x))^2)
}
sp &lt;- function(x, y) {
  sum((x-mean(x))*(y-mean(y)))
}

set.seed(1)
n &lt;- 40
x &lt;- rnorm(n, 40, 4)
a &lt;- 10
b &lt;- 5
y &lt;- a + rnorm(n, 1, 35) + b * x
dat &lt;- data.frame(x, y)

# library(ggplot2)
# ggplot(da…</description>
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        <dc:date>2026-05-31T23:55:11+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>w12.lecture.note</title>
        <link>http://www.commres.net/c/ms/2026/schedule/w12.lecture.note?rev=1780271711&amp;do=diff</link>
        <description>Regression

regression (회귀분석)
아래에서 다른 것은 이해하기 쉽지만 t.r 값과 t.b값의 (상관관계계수값과 (r), 리그레션의 계수값 (b&#039;s coefficient값)) significance level을 테스트할 때 쓰이는 se.res, se.b값을 구하는 것이 조금 복잡할 수 있다. 개념적으로\begin{eqnarray*}
\text{Standard Error of the Sample Correlation} &amp; = &amp; \sqrt{ \dfrac{ \dfrac { \text{ss.res} } { \text{ss.tot} } } { (n-2) } } \\
&amp; = &amp; \sqrt {\dfrac {(1-R^2)} {n-2} }
\end{eqnarray*}\begin{eqnarray*}
\text{Standard Error of b} &amp; = &amp; \sqrt{\dfrac{ \text{MSE} } { \text{ss(x)} }} \\
\end{eqnarray*}…</description>
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        <dc:date>2026-04-19T23:02:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>week06_t-test_and_anova_note</title>
        <link>http://www.commres.net/c/ms/2026/schedule/week06_t-test_and_anova_note?rev=1776639722&amp;do=diff</link>
        <description>see anova note



전국 고1학년 학생들의 방학 중 하루에 게임을 하는데 쓰는 시간은 140분이고 표준편차는 20분이라고 한다. 정민기학생은 미디어학과에서 만든 게임과관련된 교육프로그램을 이수하게 되면 게임에 쓰는 시간을 자제할 수 있게 된다고 생각하여 이를 검증하려고 한다.</description>
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